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This article has multiple issues. Please help improve it or discuss these issues on the talk page. (Learn how and when to remove these template messages) The following instructions should help you generate a tarball and place it online in a manner that we can all find. We have a number of guides that you can consult, if you need help. I used the macro code and I have a video file in the attachment part.Q:

How to remove from the firebase database for all images in the memory?

I have 3 collections that contain a lot of images. I would like to remove from the database those images that I use in the ImageView or BitmapArray. I did it manually, and now I was wondering if there was a way to do it automatically or automatically remove all images that are not used in the app.

A:

You cannot do this automatically. But with the DecodeFileTask.
Please read this full tutorial
How to use the DecodeFileTask

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Is this a valid proof?

$S$ and $T$ are two sets. $S\cap T\subseteq S\iff S\subseteq T$
Here $A\subseteq B$ means that $\forall x\in A$, $x\in B$. I need to prove that $S\cap T\subseteq S\iff S\subseteq T$
Now, I don’t need to prove the implication, but rather the negation. This is what I’ve done:
Suppose $S\cap T\subseteq S$. Then, $S\cap T\subseteq S$ means that $\forall x\in S\cap T$, $x\in S$. In other words, $\forall x\in S\cap T$, $x\in S$. This is equivalent to $\forall x\in S, x\in S\cap T$ which means that $S\subseteq S\cap T$. But, $S\subseteq S\cap T